If two parents who did not have Tay-Sachs gave birth to a baby with Tay- Sachs, what are their genotypes?
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Answer:
the genotype of both the parents are heterozygous .
Explanation:
tay sachs disease is inherited in an autosomal recessive manner.
in case of the both the parents are not having the disease but the progeny is affected (two recessive alleles..ex: aa) then both the parents show be heterozygous. {having one recessive and one dominant allele(Aa)}
Aa × Aa
= AA (1/4)
Aa(1/2)
aa(1/4)
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