Question

if two persons p and q are standing at a distance of 100 metre from wall and when he gives club the time interval between the two direct and reflected sound like you is 0.2 second if the speed of sound is 340 M per second in the distance between P and Q is what

Answer 1

✯Let the distance is d.

▶Draw perpendicular from the reflecting point to the line joining PQ.

So, time taken for coming directly, t= d/340

When coming after reflection,

$t = 2x \sqrt[\: \: ]{ {d}^{2} } + ( \frac{d}{2} {)}^{2}$

/340

♦ where,

D = Perpendicular distance from line PQ to the wall = 100

Difference between the two = 0.2 S

Solve for d..

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$hope \: it \: helps$

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