Question

if two pipes are opened together the tank will be filled in 6 hour the first 5 feels the tank 5 hour faster than the other how many how was it is The foster pipe take to fill the tank completely​

Answer 1

Answer:

you answer down

Step-by-step explanation:

⇒ Let the slower pipe alone can fill the reservoir in xhrs.

⇒ Then, faster pipe alone can fill the reservoir in (x−10)hrs

⇒ Part filled by slower pipe in 1hr=

x

1

⇒ Part filled by faster pipe in 1hr=

x−10

1

If pipes functyions simultaneously, the reservoir will be filled in 12hrs

⇒ Part filled by both the pipes in 1hr=

12

1

∴

x

1

+

x−10

1

=

12

1

⇒ 12(x−10)+12x=x(x−10)

⇒ 12x−120+12x=x

2

−10x

⇒ x

2

−34x+120=0

⇒ x

2

−30x−4x+120=0

⇒ x(x−30)−4(x−30)=0

⇒ (x−30)(x−4)=0

∴ x=30or4

x cannot be 4 because $$(x-10) will be negative.

∴ x=30

⇒ Hours taken by second pipe take to fill the reservoir 30hours.