Question

If two pipes function simultaneously a resirvoir will be filled in 12hours. One pipe fills the resirvor 10hours faster than the other.how many hours will the second pipe fill the resirvor

Answer 1

let first pipe be=x
and second be=y

Means if x pipe and y pipe are started simultaneously so
x pipe will fill in m hours
y pipe will fill in n hours
then.
m hours+ n hours =12

, if x pipe is 10 hours faster than y pipe means x pipe will fill in 10 hours faster than n hours
therefore 10 - 12
m hours=12-10
m hours = 2

therefore 2 hours + n hours = 12
so n hours = 12-2 = 10
n hours = 10