Question

If two point masses 1 kg and 4 kg are seperated by a distance of 2m. Magnitude of gravitational force
exerted by 1 kg on 4 kg is
a) G/4
b) G
c) G/2
d) G/3

please give the answer with explanation with the formula applied for the question ​

Answer 1

Answer:

step by step by explanation :

MA = 1 kg

MB = 4 kg

r = 2 m

F = 6.67 × 10^-11 × 1×4/(2)²

when the 4 and (2)² is cancelled.

The answer is,

F = 6.67×10^-11 N

The force exerted by A on B will be equal to gravitational constant

ie, 6.67×10^-11

The Answer is 'G'

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Answer 2

b) G

Given :

Mass of 1st body , M₁ = 1 kg

Mass of 2nd body , M₂ = 4 kg

Separated distance , r = 2 m

To Find :

Magnitude of gravitational force exerted by 1 kg and 4 kg

Formula Applied :

Gravitational force b/w two objects of masses separated by distance is given by ,

$\bigstar\ \; \sf \huge{\pink{F_G=\dfrac{G.M_1.M_2}{r^2}}}$

where ,

• F$\sf _G$ denotes gravitational force
• G denotes gravitational constant , G = 6.67 × 10⁻¹¹
• M₁ denotes mass 1
• M₂ denotes mass 2
• r denotes distance b/w two objects

Solution :

Given ,

• M₁ = 1 kg
• M₂ = 4 kg
• r = 2 m

$:\implies \sf F=\dfrac{GM_1M_2}{r^2}\\\\:\implies \sf F=\dfrac{G(1)(4)}{(2)^2}\\\\:\implies \sf F=\dfrac{4G}{4}\\\\:\implies \sf \green{F=G}\ \; \bigstar$

Option b

Magnitude of gravitational force exerted by 1 kg ang 4 kg is  G Newtons .