If two points A(2,3) and B(-6,-5) are equidistant from the point O(x,y),show that x+y+3=0.
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Distance between OA = Distance between OB,
√[(x-2)²+(y-3)²] = √[(x+6)²+(y+5)²],
on squaring both sides, we have
x²+4-4x+y²+9-6y=x²+36+12x+y²+25+10y,
-4x-6y+13=12x+10y+61,
then
-4x-6y-12x-10y=61-13,
-16x-16y=48,
-16(x+y)=48,
x+y=48/-16,
then
x+y=-3,
x+y+3=0
√[(x-2)²+(y-3)²] = √[(x+6)²+(y+5)²],
on squaring both sides, we have
x²+4-4x+y²+9-6y=x²+36+12x+y²+25+10y,
-4x-6y+13=12x+10y+61,
then
-4x-6y-12x-10y=61-13,
-16x-16y=48,
-16(x+y)=48,
x+y=48/-16,
then
x+y=-3,
x+y+3=0
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