Question

if two poles 5m and 15m high are 100 m apart then find the height of point of intersection of line joining the top of each pole to the foot of oppositepole

Answer 1

Solution :-

Assuming that 5 m high pole is at the origin and the 15 m high pole is at x = 100 m

Then, the line from the base of the 5 m pole to the top of 15 m high pole is 

⇒ y = 15x/100 ..........(1)

The line from the base of 15 m high pole to the top of 5 m high is

⇒ y = - 5x/100 + 5 ............(2)

Equating these two equations. 

⇒ 15x/100 = - 5x/100 + 5 

⇒ 0.15x = - 0.05x + 5

⇒ 0.15x + 0.05x = 5

⇒ 0.2x = 5

⇒ x = 5/0.2

⇒ x = 25

Putting the value of x = 25 in (1).

⇒ y = 15x/100

⇒ y = (15*25)/100

⇒ y = 375/100

⇒ y = 3.75 m

So, height of point of intersection is 3.75 m

Answer.

Answer 2

Answer:

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