Math, asked by arunadarshnikethan, 3 months ago

if two polynomials 2x^3+ax^2+4x-12 and x^3+x^2-2x+a leave the same remainder when divided by (x-3) find the value of a and also find the remainder​



be fast friends

Answers

Answered by shahnandani0465
2

Answer:

jvicgc vhvk. jvkk. vk jvigtckvddj. if you have any questions or you can see the attached you to try and smart ways in the the try again et now ty for ey et of the magnet tu bhi ru doing me bhi the day etc thanks to you from yet ttg

Answered by XxItzkhushixX
9

\huge\mathcal{\fcolorbox{cyan}{black}{\pink{Answer}}}

Let p(x)=2x^3 +ax ^2 +4x−12,

q(x)=x 3^ +x ^2 −2x+a.

When p(x) is divided by (x-3) the remainder is p(3). Now,

p(3)=2(3) ^3+a(3) ^2 +4(3)−12

->2(27)+a(9)+12−12

54+9a ....(1)

When q(x) is divided by (x-3) the remainder is q(3). Now,

q(3)=2(3) ^3 +(3) ^2+2(3)+a

->(27)+(9)−6+a

30+a ...(2)

Given that p(3)=q(3). That is,

54+9a=30+a (By (1) and (2))

9a−a=30−54

8a=−24

∴a=−24/8= -3

Substituting a=-3 in p(3), we get,

p(3)=54+9(−3)=54−27=27

∴ The remainder is 27.

❥︎ᴋʜᴜsʜɪ

Similar questions