Question

if two polynomials ax^3 + 4x^2 + 3x - 4 & x^3 - 4x + a leave the same remainder when divided by (x-3), find the value of a

Answer 1

Answer:

a= -1

Step-by-step explanation:

(x-3)=0

x=3

f(3)=a(3)3+4(3)2+3(3)-4

=27a+36+9-4

=27a+45-4

=27a+41

g(3)=(3)3-4(3)+a

=27-12+a

=15+a

remainders are same

27a+41=15+a

27a-a=15-41

26a=-26

a= -1