Question

If two positive integers a and b, a > b, have HCF (a, b) =x2y and LCM (a, b) = x4y3then find the possible values of a and b.

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

a*b = x6y4

Step-by-step explanation:

Relation between lcm and hcf is The product of LCM and HCF of the given natural numbers is equivalent to the product of the given numbers.

hcf *lcm = a*b

Hence,

x6y4 = a*b