Question

If two positive integers a and b are written as a = x3y2 and b = xyz ; x, y are prime numbers, then HCF (a, b) is
(A) xy
(B) xy2 (C) X3V3
(D)
X 2y2​

Answer 1

Answer:

A

Step-by-step explanation:

assume that

x=2

y=3

z=4

so

a=3x2y

a=3×2×2×3

a=36

b=xyz

b=2×3×4

b=24

then the HCF of 36,24is 6then 6is the product of x,y so, answer is xy