If two positive integers a and b are written as a= x4y2 and b=x^2y^
3, x and y are prime numbers then find the LCM (a,b)
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Answer:
LCM is x^4y^2
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The LCM of (a,b) is x^4.y^3
Given: Two positive integers a and b are written as a = x^4.y^2 and b = x^2.y^3
To Find: The LCM of (a,b).
Solution:
To find the LCM, we need to find the prime factorization of both the prime integers a and b. Then, find the highest of the powers of x and y. So,
a = x^4.y^2 = x . x . x . x . y . y
b = x^2.y^3 = x . x . y . y . y
So, LCM = x . x . x . x . y . y . y
= x^4.y^3
Hence, the LCM of (a,b) is x^4.y^3
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