Math, asked by sangk2309, 8 months ago

If two positive integers a and b are written as a= x4y2 and b=x^2y^
3, x and y are prime numbers then find the LCM (a,b)

Answers

Answered by sathyamargerate0410
2

Answer:

LCM is x^4y^2

Step-by-step explanation:

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Answered by dualadmire
0

The LCM of (a,b) is x^4.y^3

Given: Two positive integers a and b are written as a = x^4.y^2 and b = x^2.y^3

To Find: The LCM of (a,b).

Solution:

To find the LCM, we need to find the prime factorization of both the prime integers a and b. Then, find the highest of the powers of x and y. So,

   a =  x^4.y^2  =  x . x . x . x . y . y

   b =  x^2.y^3  =  x . x . y . y . y

So, LCM  =  x . x . x . x . y . y . y

               =  x^4.y^3

Hence, the LCM of (a,b) is x^4.y^3

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