if two positive integers a and b are written as a=x⁵y². and b=x²y³( x and y are prime numbers) then HCF(a,b)is (a)xy. (b)x⁵y³. (c)x³y³. (d)x²y²
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The lowest index of x is 1 and the lowest index of y is 2. HCF = xy² ab = x³y²(xy³) = x⁴y⁵. HCF × LCM = x³y³(xy²) = x⁴y⁵. Thus
When getting LCM using indices, we get the highest indices of the two and when getting HCF
Given that a = x²y³ = x × x × x × y x yb = xy³ = x × y × y × yHCF of a and b would
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