Math, asked by bandiprameela, 7 months ago

if two positive integers a and b can be expressed as a=x2y3and b=xy2, x, y are pine numbers then lcm of a, b is​

Answers

Answered by karankirat345
4

\color{green}\large\underline{\underline{Hello...}}

\color{blue}\large\underline{\underline{Answer:}}

Given:

a =  {x}^{2}  {y}^{3}

b = x {y}^{2}

To Find:

LCM (a,b)

Solution:

a = x \times x \times y \times y \times y

b = x \times y \times y

LCM (a,b)=

 {x}^{2}  {y}^{3}

\color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}}

Answered by sara122
2

Answer:

\huge \pink \star{ \green{ \boxed{ \boxed{ \boxed{ \purple{ \mathfrak{Answer}}}}}}} \pink\star</p><p>

Given:-

a =  {x}^{2} {y}

[tex]\color{blue}\large\underline{\underline{Answer:}} [/tex]

Given:

Given:a = {x}^{2} {y}^{3}a=x

Given:a = {x}^{2} {y}^{3}a=x 2

Given:a = {x}^{2} {y}^{3}a=x 2 y

Given:a = {x}^{2} {y}^{3}a=x 2 y 3

Given:a = {x}^{2} {y}^{3}a=x 2 y 3

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×y

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×y

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)=

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2 y

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2 y 3

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2 y 3

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2 y 3 \color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}}

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2 y 3 \color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}} Be...Brainly...!!!

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2 y 3 \color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}} Be...Brainly...!!!

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2 y 3 \color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}} Be...Brainly...!!!

Given:a = {x}^{2} {y}^{3}a=x 2 y 3 b = x {y}^{2}b=xy 2 To Find:LCM (a,b)Solution:a = x \times x \times y \times y \times ya=x×x×y×y×yb = x \times y \times yb=x×y×yLCM (a,b)={x}^{2} {y}^{3}x 2 y 3 \color{magenta}\large\boxed{\boxed{Be... Brainly...!!!}} Be...Brainly...!!!

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