Question

if two positive integers p and q are written as p = a^4 b^5 and q =a^2 b where a , b are prime numbers then find HCF of (p,q)​

Answer 1

Step-by-step explanation:

this is the answer of this question

Answer 2

H.C.F.(p,q)=a

H.C.F.(p,q)=a 2

H.C.F.(p,q)=a 2 b

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b 3

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b 3 pq=a

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b 3 pq=a 5

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b 3 pq=a 5 b

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b 3 pq=a 5 b 3

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b 3 pq=a 5 b 3

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b 3 pq=a 5 b 3 Therefore, L.C.M.(p,q)×H.C.F.(p,q)=pq.

H.C.F.(p,q)=a 2 bL.C.M.(p,q)=a 3 b 2 L.C.M.(p,q)×H.C.F.(p,q)=a 5 b 3 pq=a 5 b 3 Therefore, L.C.M.(p,q)×H.C.F.(p,q)=pq.Okk By