if two positive integers p and q are written as p =a-b^2 and q=a^3b,a,b are prime number then verify
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Hi ,
p = a²b³
q = a³b
HCF ( p,q ) = a²b
[ ∵Product of the smallest power of each
common prime factors in the numbers ]
LCM ( p , q ) = a³b³
[ ∵ Product of the greatest power of each
prime factors , in the numbers ]
Now ,
HCF ( p , q ) × LCM ( p , q ) = a²b × a³b³
= a∧5b∧4 --------( 1 )
[∵ a∧m × b∧n = a∧m+n ]
pq = a²b³ × a³b
= a∧5 b∧4 ---------------( 2 )
from ( 1 ) and ( 2 ) , we conclude
HCF ( p , q ) × LCM ( p ,q ) = pq
I hope this helps you.
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p = a²b³
q = a³b
HCF ( p,q ) = a²b
[ ∵Product of the smallest power of each
common prime factors in the numbers ]
LCM ( p , q ) = a³b³
[ ∵ Product of the greatest power of each
prime factors , in the numbers ]
Now ,
HCF ( p , q ) × LCM ( p , q ) = a²b × a³b³
= a∧5b∧4 --------( 1 )
[∵ a∧m × b∧n = a∧m+n ]
pq = a²b³ × a³b
= a∧5 b∧4 ---------------( 2 )
from ( 1 ) and ( 2 ) , we conclude
HCF ( p , q ) × LCM ( p ,q ) = pq
I hope this helps you.
Don't forget to mark the brainliest and rate 5 stars and press the button "thanks"..
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