If two positive integers p and q are written as p = a'b' and q = a'b : a,b are prime
numbers, then verify LCM (p,q) HCF(p,q)= pq
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Answer:
Step-by-step explanation:
p = a²b³
q = a³b
HCF ( p,q ) = a²b
[ ∵Product of the smallest power of each
common prime factors in the numbers ]
LCM ( p , q ) = a³b³
[ ∵ Product of the greatest power of each
Now ,
HCF ( p , q ) × LCM ( p , q ) = a²b × a³b³
= a∧5b∧4
And,
pq = a²b³ × a³b
= a∧5 b∧4
.: HCF ( p , q ) × LCM ( p ,q ) = pq
Hence, proved
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