If two positive integers p and q are written as p = a²b³ and q = a³b; a, b are prime numbers then verify:
LCM (p,q) × HCF (p,q) = pq
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Answered by
12
Hey there!
LCM (p, q) = a³b³
HCF (p, q) = a²b
Thus,
LCM (p, q) × HCF (p, q) = a⁵b⁴
= (a²b³) (a³ b)
= pq
Hence,
Verified LCM (p,q) × HCF (p,q) = pq
HOPE IT HELPS ^_^
LCM (p, q) = a³b³
HCF (p, q) = a²b
Thus,
LCM (p, q) × HCF (p, q) = a⁵b⁴
= (a²b³) (a³ b)
= pq
Hence,
Verified LCM (p,q) × HCF (p,q) = pq
HOPE IT HELPS ^_^
Answered by
4
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