if two projectile is thrown at different angles theta and 90-theta with same speed then addition of both's maximum height will be?
Answers
Answered by
1
Answer:
u²/2g
Explanation:
h=u²sin²Ф/2g
h1+h2= u²sin²Ф/2g + u²sin²(90-Ф)/2g
= u²/2g
manasanagireddy16:
Here u²+u²=2u² nah
Which class are you now?
11
Answered by
0
Answer:
Maximum Height=u²sin²theta/2g
In first case theta = theta
In second case theta=90 - theta
Addition of both maximum Height gives
=u²sin²theta/2g+u²sin²(90-theta)/2g
Since Sin(90- theta)=cos theta
=u²sin² theta/2g+u²cos²theta/2g
= taking 2g lcm
u²sin²theta+u²cos²theta/2g. (Since sin²theta+cos² theta=1)
=u²/2g
height is not u^2+sin^2theta/2g but u^2*sin^2theta/2g u can verify it by checking it dimenshionally too
okk
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