Question

If two resiatance of 4 ohm and 8 ohm are connected in series and current in the circuit is 5 A then pot drop across 8 ohm resistance is 32 V 48 V 40V None of these

Answer 1

Answer:

40 volts

Explanation:

Given :

• Resistance of 4 ohms and 8 ohms are connected in series

• A current of 5 Amperes passes through the circuit

To find :

• Potential difference across the 8 ohms resistor

When two resistors are connected in series, Req = r1+r2

Req = 4+8 = 12 ohms

V=IR

V=5×12

V=60 volts

Resistance for which the potential difference shall be found = 8 ohms

V=IR

V=5×8

V=40 volts

The potential difference across the 8 ohms resistor is 40 volts

Answer 2

Given that:

• Two resistances are connected in series as 4 ohm and 8 ohm.

• Amd current in the Circuit is 5 A.

To Find:

• Potential drop across 8 ohm resistance.

Formula Used:

• V = IR

Solution:

In series combination, current flowing through each resistance is same as the current in the Circuit.

So, Current through 8 ohm resistance is 5 A.

Using the above formula, we get

V = 8*5 = 40 V

So,. option C is correct.

Hope this helps