If two resistance 2 ohm and 6 ohm connected in series. And a 12 v battery connected across it. Find the total power given by the battery
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R1=2ohm
R2=6ohm
Since the connection is in series
Rs=R1+R2
= 2+6
=8ohm
Then V=12v
We have P=VI
and I=V/R
Then P=V×V/R
=12×12/8
=144/8
=18w
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