Question

If two resistances of 2 ohm and 3 ohm respectively are connected in parallel with 12 volt battery, find the total electric current through the circuit

Answer 1

Given :

• Two resistances R₁ = 2Ω and R₂ = 3Ω are connected in parallel
• Potential difference through the circuit , V = 12 V

To find :

• Current through the circuit , I = ?

Formulae :

• Equivalent resistance (R) of two resistors (R₁ and R₂) connected in parallel combination

       1/R = 1/R₁  + 1/R₂

• Relation between resistance (R) , potential difference (V) and current (I)

      R = V / I

Solution :

Calculating equivalent resistance of parallel combination (R)

→ 1/R = 1/R₁ + 1/R₂

→ 1/R = 1/(2)  + 1/(3)

→ 1/R = (3 + 2) / 6

→ 1/R = 5/6

→ R = 1.2 Ω

therefore, Equivalent resistance of circuit is 1.2 ohms.

Calculating total electric current in circuit (I)

→ R = V / I

→ 1.2 = 12 / I

→ I = 12 / 1.2

→ I = 10 A

Therefore,

The total current through the circuit is 10 Amperes.

Answer 2

Answer:

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