Question

 If two resistances of value 3 ohm and 6 ohm are connected in series and voltage of 18 volts is applied to the network, then find the voltage drop across 6 ohm resistance?​

Answer 1

Answer:

Explanation:

So total resistance R=6+3=9ohm

Because V=18

I=V/R=18/9=2A

So they are connected in series sp same current will flow through both resistor

That is 2A

Now let the voltage through 6ohm be V'

So I=V'/R

2=V'/6

V'=6*2=12V

Answer 2

Answer:

for series resistance , r= r1+ r2

then., resistance of that circuit is (3+6)=9 ohm.

and given that the voltage is 18 volts.

then the I= V/ r

I= 18/9= 2 ampere.

now, the voltage drop across 6 ohm resistor is equal to V=Ir= 6×2= 12 volt.

Explanation:

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