If two resistor of 25 ohms and 15 ohms are joined together in series and then placed in parallel with 40 ohms resistor the effective resistance of the combination
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as they are 1st connected in series so we will use R=r1+r2 and we will get value that is 40
and now we will use parallel formula that would be r = 1/r1+1/r2 so we will get 1 ohm
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Answer. Answer: Conne-cted in series = 25+30 =40 ...and then arranged in parallel with 40 ohms...so 1/R= 1/40+1/40=2/40...so, R=40/2 = 20 ohms is the effective resistance of the combination.
Explanation:
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