If two resistor of resistance 3 om and 2 om are conected in parallel to a 6 v battery then the total current in the circuit is a)1.2A b)2.5A c)5A d)7.5A
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answer is C ) 5amps
3 ohms and 2 ohms connected in // so total resistance R=r1×r2÷r1+r2
R=3×2÷3+2
R=6/5=1.2 ohms
then current I=V/R
I=6/1.2
total current I=5A
3 ohms and 2 ohms connected in // so total resistance R=r1×r2÷r1+r2
R=3×2÷3+2
R=6/5=1.2 ohms
then current I=V/R
I=6/1.2
total current I=5A
Irfanshaik1:
chesta
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