Question

If two resistors 1Ω and 5Ω are connected in parallel to a battery providing voltage 5V,

then calculate the following:-

a) Equivalent resistance

b) Current flowing through the circuit

c) Current flowing through each resistor

d) Voltage across each resistors​

Answer 1

Given :- Let the current How in 3Ω is i, and 6Ω is i1=1ampere

i1+i2=I

VA−VB=i1×3Ω=i2×6

⇒1×3=i2×6

2i=21ampere

Hence I=i1+i2=1+0.5=1.5ampere

Req=2+3+63×6=2+93×6=4Ω

equivalent circuit

Refer image .2

From KVL

1req=v

v=1.5×4

=6volt

ANSWERS..=6volt

Answer 2

Answer:

Explanation:

I)equivalent resistance=(1/1+5/1)ohm =

6ohm

2) Current flowing through the circuit

v=5v

R=6ohm

I=V/R

I=5/6

I=0.83A

4)voltage across each resistor are same bcoz we knew that voltage remain same in parallel while current divide

3) v=5v

R=1ohm

I=v/r

I=5A

Current flowimg through 2nd resistor

V=5v

R=5ohm

I=1ohm

Hope you under stand plzz make me brainlist