If two resistors 10 ohm and 20 ohm are connected in series to a 6V battery. Calculate the current flowing through the circuit and the potential difference across 10 ohm resistor.
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Answers
Answer:
I=0.2A
V across 10ohm resistor is 2V
Given,
If two resistors of resistances 10 ohms and 20 ohms are connected in series to a 6V battery.
To find,
(a) The current flowing through the circuit
(b) the potential difference across 10 ohm resistor
Solution,
We can simply solve this numerical problem by using the following process:
Mathematically,
If a set of resistors are arranged in a series type of arrangement, then the equivalent resistance of the arrangement is equal to the total of the individual resistances. Similarly, if a set of resistors are arranged in a parallel type of arrangement, then the reciprocal of the equivalent resistance of the arrangement is equal to the sum of the reciprocals of the individual resistances.
{Statement-1}
And, according to Ohm's law,
For a voltage V across the conductor, current I flowing through the conductor and resistance R provided by the conductor to the flow of current, V = RI
=> I = V/R {Statement-2}
Now, according to statement-1;
The two resistors of resistances 10 ohms and 20 ohms are connected in series
So, the equivalent resistance of the circuit
= sum of the resistance of both the resistors
= 10 ohms + 20 ohms
= 30 ohms
Now, according to statement-2;
The current flowing through the circuit
= V/R
= (voltage supply across the circuit)/(equivalent resistance of the circuit)
= (6 v)/(30 ohms)
= 1/5 A
= 0.2 A
Now, according to the question and statement-1;
The current flowing across the 10 ohms resistor
The current flowing across the 10 ohms resistor= 1/5 A
So, the potential difference across 10 ohm resistor
= RI = (resistance of the resistor)(current flowing)
= 10 ohms × 1/5 A = 2 V
Hence, the current flowing through the circuit is 0.2 A and the potential difference across 10 ohm resistor is equal to 2 V, respectively.