Question

If two resistors 10ohm and 20ohm are connected in series to a 6v battery. Calculate the current flowing through the circuit and the potential difference across 10ohm resistor.

Answer 1

here is ur answer

resistance 1 = 10ohm

resistance 2 = 20 ohm

potential difference = 6 volt

${ \bold{ \: according \: to \: the \: question}}$

the resistors are connected in series

■■ for series combination,

equivalent resistance = resistance 1 + resistance 2

R equivalent = 10 ohm + 20 ohm

= 30 ohm

Ohm' s law,,

${ \huge{ \: resistance \: = \frac{potential \: difference}{current} }}$

R equivalent = V/ I

current (I) = potential difference/ R equivalent

= 6volt / 30ohm = 0.2 ampere

current flowing through 10 ohm resistor = (10 ohm/ 30ohm)× 0.2 ampere

= 0.2/ 3 ampere

potential difference across 10ohm resistor = current × resistance

= 0.2/ 3 ampere × 10 ohm

= 2/ 3 volt