if two resistors 6 ohm and 2 ohm are connected in parallel and then placed in series with 6 ohm resistor draw the circuit diagram and find the effective resistance
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Explanation:
effective resistance
when resistance is in parallel
R1= 6ohm and R2 =2ohm
Rparallel = R1*R2/R1+R2
= 12/8
Now resistance is in series with Rparallel
therefore
effective resistance = Rseries+Rparallel
= 12/8+6
= 7.5ohm
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