Question

If two resistors having resistance of 16 ohm and 40 are connected in series and potential difference across them is 18 volt then calculate current flowing through the circuit

Answer 1

Answer:

• Current through the circuit = 0.32 A (approx.)

Explanation:

Given two resistors of resistances 16 Ω and 40 Ω are connected in series,

so, calculating equivalent resistances

→ R(eq) = R₁ + R₂

→ R(eq) = 16 Ω + 40 Ω

→ R(eq) = 56 Ω

Now,

Given that the potential difference through the circuit is 18 V

We need to calculate

the current flowing through the circuit, I =?

Using Ohm's law

→ Potential difference = current × resistance

→ 18  = I × 56

→ I = 18 / 56

→ I = 0.32 A

Therefore,

• Approximate current through the circuit is 0.32 Amperes.

Answer 2

Given:

• R1= 16 Ω
• R2 = 40 Ω
• Potential difference = V= 18 Volt

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Need to find:

• Current = I =?

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Solution :

In series connection,

${R}_{Equivalent} = {R}_1+{R}_{2}$

$\implies {R}_{Equivalent}$ = 16Ω + 40Ω

$\purple{\bold{\boxed{{R}_{Equivalent} = 56 Ω}}}$

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From Ohm's law, We know,

V= IR

Substituting the values we get,

$18 = \: I \times 56$

$\implies \: I = \dfrac{18}{56}$

$\red{\bold{\boxed{\large{\implies I= 0.321428 A}}} }$