if two resistors of resistance 5 ohm and 10 ohm respect respectively are connected to a battery of of EMF 6 volt then determine the value of total resistance and current in the circuit when they are connected in parallel combination second series combination
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Answer:
total resistance when connected in parallel =
1/(1/5+1/10) = 10/3 and current = 6/(10/3)=18/10
= 1.8 amp
total resistance when connected in series=
5+10 = 15 and current will be =6/15 = 2/5 = 0.4 amp Ans
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0
Answer:
total resistance when connected in parallel 1 upon 1 upon 5 + 1 upon 10 equal 10.3 and current 6.10.3 equal 18.10 equal 1.8 a MP total resistance when connected in series 5 + 10 equal 15 current will be 6.15 equal to upon 5 equal 40.4 MT
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