If two roots of a quadratic equation are √2 and 1 then form the quadratic equation.
Answers
Answered by
58
Let α and β are the roots of a quadratic equation.
Given: (α)= √2 , β= 1
Sum of zeroes (α+ β)= (√2+1)
(α+ β)= (√2+1)
Product of zeroes (α. β) = √2 × 1= √2
α. β = √2
Required quadratic equation= k [x²-(Sum of zeroes)x +( Product of zeroes)]
= k[ x² -(α+ β)x +(α. β], where k is a non zero real number.
= x² -(√2+1)x + √2 [ here k = 1]
Hence, a quadratic equation is = x² -(√2+1)x + √2.
HOPE THIS WILL HELP YOU...
Given: (α)= √2 , β= 1
Sum of zeroes (α+ β)= (√2+1)
(α+ β)= (√2+1)
Product of zeroes (α. β) = √2 × 1= √2
α. β = √2
Required quadratic equation= k [x²-(Sum of zeroes)x +( Product of zeroes)]
= k[ x² -(α+ β)x +(α. β], where k is a non zero real number.
= x² -(√2+1)x + √2 [ here k = 1]
Hence, a quadratic equation is = x² -(√2+1)x + √2.
HOPE THIS WILL HELP YOU...
Answered by
18
HEYA MATE!!
GIVEN,
ZEROS==>
,1.
LET THE ZEROS BE α,β.
α+β==>(√2+1) ...(I)
α.β==>(√2*1)==>(√2) ....(II)
QUADRATIC EQUATION ==>
x²-(α+β)x+(α.β)
==>x²-(√2+1)+√2[ANSWER]
HOPE IT HELPS YOU ☺☺☺
GIVEN,
ZEROS==>
,1.
LET THE ZEROS BE α,β.
α+β==>(√2+1) ...(I)
α.β==>(√2*1)==>(√2) ....(II)
QUADRATIC EQUATION ==>
x²-(α+β)x+(α.β)
==>x²-(√2+1)+√2[ANSWER]
HOPE IT HELPS YOU ☺☺☺
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