If two s.H.M.'s are represented by equations y1=10 sin[3pit+pi/4] and y2=5[sin (3pit)+31/2cos(3pit)],then find the ratio of their amplitudes & phase difference in b/w them.
Answers
Answered by
7
Hey mate,
◆ Answer-
Ratio of amplitudes = 2
Phase difference = π/4 rad
◆ Explaination-
# Given-
Comparing both eqn with std form y = A.sin(wt+θ),
We can say that -
A1 = 10 units
θ1 = π/4 rad
A2 = 5 units
θ2 = 0 rad
w = 3π
# Calculations
Ratio of amplitudes-
A1/A2 = 10/5 = 2
Phase difference-
φ = θ1 - θ2 = π/4 rad
Hope this helps you...
◆ Answer-
Ratio of amplitudes = 2
Phase difference = π/4 rad
◆ Explaination-
# Given-
Comparing both eqn with std form y = A.sin(wt+θ),
We can say that -
A1 = 10 units
θ1 = π/4 rad
A2 = 5 units
θ2 = 0 rad
w = 3π
# Calculations
Ratio of amplitudes-
A1/A2 = 10/5 = 2
Phase difference-
φ = θ1 - θ2 = π/4 rad
Hope this helps you...
queerburdy:
the answer is wrong.
Answered by
3
Answer:
ratio of amplitude is equal to 1
phase difference is is π/12
Attachments:
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