If two sides a, b and angle A be such that two triangles are formed, then the sum of the values of the third side is
1] 2b sin A
2] 2b cos A
3] b/a cos A
4] (c + b) cos A
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4] (c + b) cos A
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Please mark the answer as brain list answer
PradneshM:
how to solve
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The sum of the values of the third side is 2b cos A
Let the first root of quadratic equation be = c1
Let the second root of quadratic equation be = c2
From cosine formula, the equation will be -
a² = b² + c² - 2 bc Cos A or
= c² - (2bcos A)c + b² - a² = 0, that is quadratic in point c
Therefore, as c1 and c2 are the roots of quadratic equation then, -
The sum of two values of the third side will be -
c1 + c2 = 2b cos A
Thus, the value of the third side is 2b cos A.
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