If two sides of a triangle are 6, 8 and 10 which triangle is it
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Let c=10 a= 8 b= 6
By using Pythagoras theorem
c²= a²+b²
(10)²= (8)²+(6)²
100= 64+36
100 = 100
Hence it is a right angled ∆
In any right Angle ∆ the sum of the squares of the lengths of both legs is the same as the square of the length of the hypotenuse.
By using Pythagoras theorem
c²= a²+b²
(10)²= (8)²+(6)²
100= 64+36
100 = 100
Hence it is a right angled ∆
In any right Angle ∆ the sum of the squares of the lengths of both legs is the same as the square of the length of the hypotenuse.
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