Question

If two sides of a triangle are unequal, prove that the longer side has the greater angle opposite to it

Answer 1

Answer:

here is your answer dude

Step-by-step explanation:

In A ABC, let AC > AB.

Mark point D on AC such that AB = AD and join BD.

In A ABD, AB AD

: <ABD = ZADB

ZADB is exterior angle of ABCD

ZADB > ZACB

ZABD > ZACB

But ABC ABD >

ZABC > ZACB

Thus, the longer side, AC, has greater angle, ZABC, opposite it.

Hence proved.

Answer 2

Answer:

Your answer is in above picture

hope it helps you❤