Question

if two sides of a triangle are unequal ,then the angle opposite to the longer side is larger​

Answer 1

then the opposite side of the trimgle is equal

Answer 2

Given: △ABC, AB>AC

To Prove: ∠ACB>∠ABC

Construction: Make a point D on AB such that AD=AC and join DC

In △ACD,

AD=AC

∠ACD=∠ADC (Angles opposite to equal sides)

But ∠ADC>∠ABC (Exterior angle of the triangle is greater than the opposite interior angle)

Again, ∠ACB>∠ACD (D lies in interior of ∠ACB)

Thus, ∠ACB>∠ABC

solution

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In the above figure, AD is the bisector of ∠BAC. Prove that AB>BD.