if two sides of triangles are 8 cm and 11 cm . if its parameter is 32 cm .find its area
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Heya !!!
Let ABC is a triangle
Let,
AB = 8 cm , AC = 11 cm and BC = ?
Given that,
Perimeter of triangle = 32 cm
AB + BC + AC = 32
8 + BC+ 11 = 32
BC = 32 - 19
BC = 13 cm
Semi perimeter = 1/2 × ( AB + BC + AC )
=> 1/2 × ( 8 + 13 + 11)
=>16 cm
Therefore,
Area of triangle = ✓S ( S - A) ( S - B ) ( S -C)
=> ✓16 ( 16 - 8 ) ( 16 - 13) ( 16 - 11)
=> ✓16 × 8 × 3 × 5
=> 4 × ✓ 2 × 2 × 2 × 3 × 5
=> 4 × 2 ✓2 × 3 × 5
=> 8✓30 cm².
★ HOPE IT WILL HELP YOU ★
Let ABC is a triangle
Let,
AB = 8 cm , AC = 11 cm and BC = ?
Given that,
Perimeter of triangle = 32 cm
AB + BC + AC = 32
8 + BC+ 11 = 32
BC = 32 - 19
BC = 13 cm
Semi perimeter = 1/2 × ( AB + BC + AC )
=> 1/2 × ( 8 + 13 + 11)
=>16 cm
Therefore,
Area of triangle = ✓S ( S - A) ( S - B ) ( S -C)
=> ✓16 ( 16 - 8 ) ( 16 - 13) ( 16 - 11)
=> ✓16 × 8 × 3 × 5
=> 4 × ✓ 2 × 2 × 2 × 3 × 5
=> 4 × 2 ✓2 × 3 × 5
=> 8✓30 cm².
★ HOPE IT WILL HELP YOU ★
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Heya mate
here is your answer
I hope this will help u...✌️✌️
thank u:-)
here is your answer
I hope this will help u...✌️✌️
thank u:-)
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