If two small force of + 9 microcoulomb and minus 4
microcoulomb and are attracted with a force f if the - 5 microcoulomb is added to one of them then the resultant force will be
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PHYSICS
Two particles having charges q
1
and q
2
when kept at a certain distance, exert force F on each other. If distance is reduced to half, force between them becomes :
December 26, 2019avatar
Ribiyana Suryadevara
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ANSWER
Answer is C.
Coulomb's law describes the magnitude of the electrostatic force between two electric charges. The Coulomb's law formula is given as follows.
The force between 2 charges q
1
and q
2
is given by the formula F=k
r
2
q
1
×q
2
.
Where, q
1
: Charge of object 1
q
2
: Charge of object 2
r: Distance between the two objects
F: Force between the two objects. A positive force implies a repulsive interaction, while a negative force implies an attractive interaction
k: Coulomb Constant.
In this case, the distance between 2 charges is halved. So the new force becomes F
new
=k
(
2
r
)
2
q
1
×q
2
=
r
2
4×k×q
1
×q
2
=4F.
Hence, the force between the charges becomes 4F.