Question

if two soap bubbles have radii in the ratio of 1:2 then the ratio of excess pressure will be

Answer 1

Answer:

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Answer 2

The ratio of excess pressure will be 2:1.

Explanation:

The excess pressure in soap bubble is given as

$P=\frac{4T}{R}$

Here T is the surface tension of soap and R is the radius of the soap.

So, for first bubble

$P_{1} =\frac{4T}{R_{1} }$

For second bubble,

$P_{2} =\frac{4T}{R_{2} }$

Given $\frac{R_{1} }{R_{2} } =\frac{1}{2}$.

Therefore from both the above formula,we get

$\frac{P_{1} }{P_{2} } =\frac{R_{2} }{R_{1} } =\frac{2}{1}$

Thus, the ratio of excess pressure will be 2:1.

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