Question

if two soap bubbles have radii in the ratio of 1:2 then the ratio of excess pressure will be

Answer 1

If two soap bubbles have radii in the ratio of 1:2 then the ratio of excess pressure will be 2:1

- given:- R1/R2 = 1/2

- excess pressure for soap bubble is given by:- p= 4S/R

- So, p1/p2 = (4S/R1)/(4S/R2)

p1/p2 = R2/R1

p1/p2 = 2/1

- so final answer is p1:p2 = 2:1

Answer 2

Ratio of excess pressure = 1:2

Explanation:

The excess pressure inside a soap bubble is denoted by the formula:

Delta P = 4T / R

We infer that the excess pressure is inversely proportional to the radius for a given fluid.

Delta P ∝ R^-1  

Given that two soap bubbles have radii in the ratio of 1:2.

So the ratio of excess pressure in the two soap bubbles will be in the ratio 1:2 (inverse of radius ratio).