Question

If two soap bubbles have radii in the ratio of 1:2 then the ratio of excess pressure will be?​

Answer 1

≡QUESTION≡

If two soap bubbles have radii in the ratio of 1:2 then what is the ratio of  the excess pressure ?​

                                                         

║⊕ANSWER⊕║

The excess pressure inside a soap bubble is denoted by the formula:

Δ P = 4S / R

Excess pressure is inversely proportional to the radius for a given fluid.

GIVEN

R₁/R₂ = 1/2

p₁/p₂ = (4S/R₁) / (4S/R₂)

p₁/p₂ = R₂/R₁

p₁/p₂ = 2/1

∴ The ratio of excess pressure in the two soap bubbles will be in the ratio 2:1 (inverse of radius ratio).

                                                         

Answer 2

Answer:

Ratio of excess pressure is 2 : 1

Explanation:

We Have :-

Ratio of Radius of two soap bubbles = 1 : 2

To Find :-

Excess pressure inside the soap bubbles

Solution :-

Let the radii be x₁ and x₂

x₁ / x₂ = 1 / 2

Let α be the surface tension

Excess Pressure

Drop 1 = 4 α / x₁

Drop 2 = 4 α / x₂

Pressure

Drop 1 / Drop 2 = 2 / 1

Ratio = 2 : 1

Ratio of excess pressure is 2 : 1