If two solutions of pH 9 and pH6 are mixed in equal proportions. What will be the approximate pH of the solution
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Answer:
pH=4, pH=6
For pH=4, [H
+
]=10
−4
M
For pH=6, [H
+
]=10
−6
M
Molarity=
volume
no. of moles
Let the volume be V.
No. of moles, n
1
=10
−4
×V
No. of moles, n
2
=10
−6
×V
Net number of moles after mixing = 10
−4
×V+10
−6
×V
Net [H
+
] concentration =
2V
10
−4
×V+10
−6
×V
pH = −log[H
+
]
pH = 4.3
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