Question

if two straight lines 3 x - 2y = 8 and 2 x - y = 5 lie along the two diameters of a circle which touches the x axis, find the equation of the circle.​

Answer 1

Step-by-step explanation:

center of the circle will be point where both lines cross each other

3x-2y=8

2x-y=5

multiply 2nd one with 2 and subtract them

-x=-2

x=2

y=-1

since circle touches x axis implies radius is equal to distance of center from x axis =1

r=1

(x-2)^2 +(y+1)^2=1

x^2+y^2-4x+2y +4=0

Answer 2

See the attachment please....