if two sum ofnatural number is 40 and their difference is 10. what are the numbers
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let the 1st unknown number be x and the 2nd unknown number be y.
here x + y= 40
and x - y =10
x + y - (x - y)= 40 - 10
x - x + y + y = 30
2y = 30
y = 30/2
y = 15
so x = 40 - 15 = 25
or
x = 15 + 10 =25
there fore ,
x = 25 and y = 10 whose sum is 40 and difference is 10.
hope it helps !!
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