If two supplementary angles differ by 44 degree , then one of the angle is what ?
shwetakarhale:
one angle will be 54 degree
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Let one angle be X
Then the others angle = X + 44
.
A/q X + (x+44) = 180 ( supplementary angles)
2x = 180-44
x= 136/2
X = 68
Then the others angle = X + 44
.
A/q X + (x+44) = 180 ( supplementary angles)
2x = 180-44
x= 136/2
X = 68
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