Question

If two supplementary angles the measure of one angle is 6 more than twice the measure of the other find the measure of these two angles

Answer 1

Given :

• In two supplementary angles , the measure of one angle is 6 more than twice the measure of the other angle .

To Find :

• Measure of angles .

Solution :

$\longmapsto\tt{Let\:one\:angle\:be=x}$

$\longmapsto\tt{Other\:angle=2x+6}$

Now ,

As we know that sum of two supplementary angles is 180° . So ,

$\longmapsto\tt{x+2x+6=180^{\circ}}$

$\longmapsto\tt{3x+6=180}$

$\longmapsto\tt{3x=180-6}$

$\longmapsto\tt{3x=174}$

$\longmapsto\tt{x=\cancel\dfrac{174}{3}}$

$\longmapsto\tt\bf{x=58^{\circ}}$

Value of x is 58° .

Therefore :

$\longmapsto\tt{Measure\:of\:one\:angle=x}$

$\longmapsto\tt\bf{58^{\circ}}$

$\longmapsto\tt{Measure\:of\:other\:angle=2x+6}$

$\longmapsto\tt{2(58)+6}$

$\longmapsto\tt\bf{122^{\circ}}$

So , The measure of two angles are 58° and 122° .

Answer 2

Answer:

Given :-

In two supplementary angles , the measure of one angle is 6 more than twice the measure of the other angle .

To Find :-

Angles

Solution :-

Let the angle be y and 2y + 6.

Now,

We know that Supplement of two angles is 180⁰

$\implies$ y + 2y + 6 = 180

$\implies$ 3y + 6 = 180

$\implies$ 3y = 180 - 6

$\implies$ 3y = 174

$\implies$ y = 174/3

$\implies$ y = 58⁰

Now,

2y + 6 = 2(58) + 6 = 116 + 6 = 122⁰

Therefore

${ \textsf{ \textbf{ \red{ \underline{ The \: measure \: of \: angles \: are \: 58 \: and \: 122}}}}}$