Question

if two supplementry angles are 2x-9 and x+6​

Answer 1

89

89

89

89

89

89

89

89

89

89

Answer 2

supplementary =180°

supplementary =180° 2x-9+x+6=180°

supplementary =180° 2x-9+x+6=180° 2x+x+(-9+6)=180°

supplementary =180° 2x-9+x+6=180° 2x+x+(-9+6)=180°3x+(-3)=180°

supplementary =180° 2x-9+x+6=180° 2x+x+(-9+6)=180°3x+(-3)=180°3x=180-3

supplementary =180° 2x-9+x+6=180° 2x+x+(-9+6)=180°3x+(-3)=180°3x=180-3 3x=177°

supplementary =180° 2x-9+x+6=180° 2x+x+(-9+6)=180°3x+(-3)=180°3x=180-3 3x=177°x=177/3

supplementary =180° 2x-9+x+6=180° 2x+x+(-9+6)=180°3x+(-3)=180°3x=180-3 3x=177°x=177/3x=59

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