If two tangents inclined at an angle 60 are drawn to a circle of radius 5cm,find the length of each tangent.
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Answered by
11
tan30 = 5/tangent,
1/√3 = 5/tangent,
then
tangent =5√3
1/√3 = 5/tangent,
then
tangent =5√3
Answered by
14
Radius = 5cm
we know PA = PB
OA=OB=5cm
∆PBO is right angle triangle
|_B=90°
Tan30 = OB/PB
1/√3 = 5/PB
PB=5√3
similarly
∆POA is right angle triangle
|_A=90°
Tan30°= OA/PA
1/√3= 5/PA
PA= 5√3
we know PA = PB
OA=OB=5cm
∆PBO is right angle triangle
|_B=90°
Tan30 = OB/PB
1/√3 = 5/PB
PB=5√3
similarly
∆POA is right angle triangle
|_A=90°
Tan30°= OA/PA
1/√3= 5/PA
PA= 5√3
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