if two tangents inclined at an angle of 60 are drawn to circle of radius 3m
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Step-by-step explanation:
Let PA and PB be the two tangents to a circle with centre O and radius 3
∴∠APO=∠BPO
=
2
1
×∠APB
=
2
1
×60
0
=30
0
Also, OA⊥AP and OB⊥BP
In a right angled triangle OAP,
tan30
0
=
PA
3
⇒
3
1
=
PA
3
⇒PA=3
3
cm
⇒PA=PB=3
3
cm
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